3.5.81 \(\int \frac {A+B x}{\sqrt {e x} (a+c x^2)^{5/2}} \, dx\) [481]

3.5.81.1 Optimal result
3.5.81.2 Mathematica [C] (verified)
3.5.81.3 Rubi [A] (verified)
3.5.81.4 Maple [A] (verified)
3.5.81.5 Fricas [C] (verification not implemented)
3.5.81.6 Sympy [C] (verification not implemented)
3.5.81.7 Maxima [F]
3.5.81.8 Giac [F]
3.5.81.9 Mupad [F(-1)]

3.5.81.1 Optimal result

Integrand size = 24, antiderivative size = 335 \[ \int \frac {A+B x}{\sqrt {e x} \left (a+c x^2\right )^{5/2}} \, dx=\frac {\sqrt {e x} (A+B x)}{3 a e \left (a+c x^2\right )^{3/2}}+\frac {\sqrt {e x} (5 A+3 B x)}{6 a^2 e \sqrt {a+c x^2}}-\frac {B x \sqrt {a+c x^2}}{2 a^2 \sqrt {c} \sqrt {e x} \left (\sqrt {a}+\sqrt {c} x\right )}+\frac {B \sqrt {x} \left (\sqrt {a}+\sqrt {c} x\right ) \sqrt {\frac {a+c x^2}{\left (\sqrt {a}+\sqrt {c} x\right )^2}} E\left (2 \arctan \left (\frac {\sqrt [4]{c} \sqrt {x}}{\sqrt [4]{a}}\right )|\frac {1}{2}\right )}{2 a^{7/4} c^{3/4} \sqrt {e x} \sqrt {a+c x^2}}-\frac {\left (3 \sqrt {a} B-5 A \sqrt {c}\right ) \sqrt {x} \left (\sqrt {a}+\sqrt {c} x\right ) \sqrt {\frac {a+c x^2}{\left (\sqrt {a}+\sqrt {c} x\right )^2}} \operatorname {EllipticF}\left (2 \arctan \left (\frac {\sqrt [4]{c} \sqrt {x}}{\sqrt [4]{a}}\right ),\frac {1}{2}\right )}{12 a^{9/4} c^{3/4} \sqrt {e x} \sqrt {a+c x^2}} \]

output
1/3*(B*x+A)*(e*x)^(1/2)/a/e/(c*x^2+a)^(3/2)+1/6*(3*B*x+5*A)*(e*x)^(1/2)/a^ 
2/e/(c*x^2+a)^(1/2)-1/2*B*x*(c*x^2+a)^(1/2)/a^2/c^(1/2)/(a^(1/2)+x*c^(1/2) 
)/(e*x)^(1/2)+1/2*B*(cos(2*arctan(c^(1/4)*x^(1/2)/a^(1/4)))^2)^(1/2)/cos(2 
*arctan(c^(1/4)*x^(1/2)/a^(1/4)))*EllipticE(sin(2*arctan(c^(1/4)*x^(1/2)/a 
^(1/4))),1/2*2^(1/2))*(a^(1/2)+x*c^(1/2))*x^(1/2)*((c*x^2+a)/(a^(1/2)+x*c^ 
(1/2))^2)^(1/2)/a^(7/4)/c^(3/4)/(e*x)^(1/2)/(c*x^2+a)^(1/2)-1/12*(cos(2*ar 
ctan(c^(1/4)*x^(1/2)/a^(1/4)))^2)^(1/2)/cos(2*arctan(c^(1/4)*x^(1/2)/a^(1/ 
4)))*EllipticF(sin(2*arctan(c^(1/4)*x^(1/2)/a^(1/4))),1/2*2^(1/2))*(3*B*a^ 
(1/2)-5*A*c^(1/2))*(a^(1/2)+x*c^(1/2))*x^(1/2)*((c*x^2+a)/(a^(1/2)+x*c^(1/ 
2))^2)^(1/2)/a^(9/4)/c^(3/4)/(e*x)^(1/2)/(c*x^2+a)^(1/2)
 
3.5.81.2 Mathematica [C] (verified)

Result contains higher order function than in optimal. Order 5 vs. order 4 in optimal.

Time = 10.10 (sec) , antiderivative size = 140, normalized size of antiderivative = 0.42 \[ \int \frac {A+B x}{\sqrt {e x} \left (a+c x^2\right )^{5/2}} \, dx=\frac {5 A x \left (a+c x^2\right ) \sqrt {1+\frac {c x^2}{a}} \operatorname {Hypergeometric2F1}\left (\frac {1}{4},\frac {1}{2},\frac {5}{4},-\frac {c x^2}{a}\right )+x \left (7 a A+5 a B x+5 A c x^2+3 B c x^3-B x \left (a+c x^2\right ) \sqrt {1+\frac {c x^2}{a}} \operatorname {Hypergeometric2F1}\left (\frac {1}{2},\frac {3}{4},\frac {7}{4},-\frac {c x^2}{a}\right )\right )}{6 a^2 \sqrt {e x} \left (a+c x^2\right )^{3/2}} \]

input
Integrate[(A + B*x)/(Sqrt[e*x]*(a + c*x^2)^(5/2)),x]
 
output
(5*A*x*(a + c*x^2)*Sqrt[1 + (c*x^2)/a]*Hypergeometric2F1[1/4, 1/2, 5/4, -( 
(c*x^2)/a)] + x*(7*a*A + 5*a*B*x + 5*A*c*x^2 + 3*B*c*x^3 - B*x*(a + c*x^2) 
*Sqrt[1 + (c*x^2)/a]*Hypergeometric2F1[1/2, 3/4, 7/4, -((c*x^2)/a)]))/(6*a 
^2*Sqrt[e*x]*(a + c*x^2)^(3/2))
 
3.5.81.3 Rubi [A] (verified)

Time = 0.45 (sec) , antiderivative size = 324, normalized size of antiderivative = 0.97, number of steps used = 11, number of rules used = 10, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.417, Rules used = {551, 27, 551, 27, 556, 555, 1512, 27, 761, 1510}

Below are the steps used by Rubi to obtain the solution. The rule number used for the transformation is given above next to the arrow. The rules definitions used are listed below.

\(\displaystyle \int \frac {A+B x}{\sqrt {e x} \left (a+c x^2\right )^{5/2}} \, dx\)

\(\Big \downarrow \) 551

\(\displaystyle \frac {\sqrt {e x} (A+B x)}{3 a e \left (a+c x^2\right )^{3/2}}-\frac {\int -\frac {5 A+3 B x}{2 \sqrt {e x} \left (c x^2+a\right )^{3/2}}dx}{3 a}\)

\(\Big \downarrow \) 27

\(\displaystyle \frac {\int \frac {5 A+3 B x}{\sqrt {e x} \left (c x^2+a\right )^{3/2}}dx}{6 a}+\frac {\sqrt {e x} (A+B x)}{3 a e \left (a+c x^2\right )^{3/2}}\)

\(\Big \downarrow \) 551

\(\displaystyle \frac {\frac {\sqrt {e x} (5 A+3 B x)}{a e \sqrt {a+c x^2}}-\frac {\int -\frac {5 A-3 B x}{2 \sqrt {e x} \sqrt {c x^2+a}}dx}{a}}{6 a}+\frac {\sqrt {e x} (A+B x)}{3 a e \left (a+c x^2\right )^{3/2}}\)

\(\Big \downarrow \) 27

\(\displaystyle \frac {\frac {\int \frac {5 A-3 B x}{\sqrt {e x} \sqrt {c x^2+a}}dx}{2 a}+\frac {\sqrt {e x} (5 A+3 B x)}{a e \sqrt {a+c x^2}}}{6 a}+\frac {\sqrt {e x} (A+B x)}{3 a e \left (a+c x^2\right )^{3/2}}\)

\(\Big \downarrow \) 556

\(\displaystyle \frac {\frac {\sqrt {x} \int \frac {5 A-3 B x}{\sqrt {x} \sqrt {c x^2+a}}dx}{2 a \sqrt {e x}}+\frac {\sqrt {e x} (5 A+3 B x)}{a e \sqrt {a+c x^2}}}{6 a}+\frac {\sqrt {e x} (A+B x)}{3 a e \left (a+c x^2\right )^{3/2}}\)

\(\Big \downarrow \) 555

\(\displaystyle \frac {\frac {\sqrt {x} \int \frac {5 A-3 B x}{\sqrt {c x^2+a}}d\sqrt {x}}{a \sqrt {e x}}+\frac {\sqrt {e x} (5 A+3 B x)}{a e \sqrt {a+c x^2}}}{6 a}+\frac {\sqrt {e x} (A+B x)}{3 a e \left (a+c x^2\right )^{3/2}}\)

\(\Big \downarrow \) 1512

\(\displaystyle \frac {\frac {\sqrt {x} \left (\left (5 A-\frac {3 \sqrt {a} B}{\sqrt {c}}\right ) \int \frac {1}{\sqrt {c x^2+a}}d\sqrt {x}+\frac {3 \sqrt {a} B \int \frac {\sqrt {a}-\sqrt {c} x}{\sqrt {a} \sqrt {c x^2+a}}d\sqrt {x}}{\sqrt {c}}\right )}{a \sqrt {e x}}+\frac {\sqrt {e x} (5 A+3 B x)}{a e \sqrt {a+c x^2}}}{6 a}+\frac {\sqrt {e x} (A+B x)}{3 a e \left (a+c x^2\right )^{3/2}}\)

\(\Big \downarrow \) 27

\(\displaystyle \frac {\frac {\sqrt {x} \left (\left (5 A-\frac {3 \sqrt {a} B}{\sqrt {c}}\right ) \int \frac {1}{\sqrt {c x^2+a}}d\sqrt {x}+\frac {3 B \int \frac {\sqrt {a}-\sqrt {c} x}{\sqrt {c x^2+a}}d\sqrt {x}}{\sqrt {c}}\right )}{a \sqrt {e x}}+\frac {\sqrt {e x} (5 A+3 B x)}{a e \sqrt {a+c x^2}}}{6 a}+\frac {\sqrt {e x} (A+B x)}{3 a e \left (a+c x^2\right )^{3/2}}\)

\(\Big \downarrow \) 761

\(\displaystyle \frac {\frac {\sqrt {x} \left (\frac {3 B \int \frac {\sqrt {a}-\sqrt {c} x}{\sqrt {c x^2+a}}d\sqrt {x}}{\sqrt {c}}+\frac {\left (\sqrt {a}+\sqrt {c} x\right ) \sqrt {\frac {a+c x^2}{\left (\sqrt {a}+\sqrt {c} x\right )^2}} \left (5 A-\frac {3 \sqrt {a} B}{\sqrt {c}}\right ) \operatorname {EllipticF}\left (2 \arctan \left (\frac {\sqrt [4]{c} \sqrt {x}}{\sqrt [4]{a}}\right ),\frac {1}{2}\right )}{2 \sqrt [4]{a} \sqrt [4]{c} \sqrt {a+c x^2}}\right )}{a \sqrt {e x}}+\frac {\sqrt {e x} (5 A+3 B x)}{a e \sqrt {a+c x^2}}}{6 a}+\frac {\sqrt {e x} (A+B x)}{3 a e \left (a+c x^2\right )^{3/2}}\)

\(\Big \downarrow \) 1510

\(\displaystyle \frac {\frac {\sqrt {x} \left (\frac {\left (\sqrt {a}+\sqrt {c} x\right ) \sqrt {\frac {a+c x^2}{\left (\sqrt {a}+\sqrt {c} x\right )^2}} \left (5 A-\frac {3 \sqrt {a} B}{\sqrt {c}}\right ) \operatorname {EllipticF}\left (2 \arctan \left (\frac {\sqrt [4]{c} \sqrt {x}}{\sqrt [4]{a}}\right ),\frac {1}{2}\right )}{2 \sqrt [4]{a} \sqrt [4]{c} \sqrt {a+c x^2}}+\frac {3 B \left (\frac {\sqrt [4]{a} \left (\sqrt {a}+\sqrt {c} x\right ) \sqrt {\frac {a+c x^2}{\left (\sqrt {a}+\sqrt {c} x\right )^2}} E\left (2 \arctan \left (\frac {\sqrt [4]{c} \sqrt {x}}{\sqrt [4]{a}}\right )|\frac {1}{2}\right )}{\sqrt [4]{c} \sqrt {a+c x^2}}-\frac {\sqrt {x} \sqrt {a+c x^2}}{\sqrt {a}+\sqrt {c} x}\right )}{\sqrt {c}}\right )}{a \sqrt {e x}}+\frac {\sqrt {e x} (5 A+3 B x)}{a e \sqrt {a+c x^2}}}{6 a}+\frac {\sqrt {e x} (A+B x)}{3 a e \left (a+c x^2\right )^{3/2}}\)

input
Int[(A + B*x)/(Sqrt[e*x]*(a + c*x^2)^(5/2)),x]
 
output
(Sqrt[e*x]*(A + B*x))/(3*a*e*(a + c*x^2)^(3/2)) + ((Sqrt[e*x]*(5*A + 3*B*x 
))/(a*e*Sqrt[a + c*x^2]) + (Sqrt[x]*((3*B*(-((Sqrt[x]*Sqrt[a + c*x^2])/(Sq 
rt[a] + Sqrt[c]*x)) + (a^(1/4)*(Sqrt[a] + Sqrt[c]*x)*Sqrt[(a + c*x^2)/(Sqr 
t[a] + Sqrt[c]*x)^2]*EllipticE[2*ArcTan[(c^(1/4)*Sqrt[x])/a^(1/4)], 1/2])/ 
(c^(1/4)*Sqrt[a + c*x^2])))/Sqrt[c] + ((5*A - (3*Sqrt[a]*B)/Sqrt[c])*(Sqrt 
[a] + Sqrt[c]*x)*Sqrt[(a + c*x^2)/(Sqrt[a] + Sqrt[c]*x)^2]*EllipticF[2*Arc 
Tan[(c^(1/4)*Sqrt[x])/a^(1/4)], 1/2])/(2*a^(1/4)*c^(1/4)*Sqrt[a + c*x^2])) 
)/(a*Sqrt[e*x]))/(6*a)
 

3.5.81.3.1 Defintions of rubi rules used

rule 27
Int[(a_)*(Fx_), x_Symbol] :> Simp[a   Int[Fx, x], x] /; FreeQ[a, x] &&  !Ma 
tchQ[Fx, (b_)*(Gx_) /; FreeQ[b, x]]
 

rule 551
Int[((e_.)*(x_))^(m_)*((c_) + (d_.)*(x_))*((a_) + (b_.)*(x_)^2)^(p_), x_Sym 
bol] :> Simp[(-(e*x)^(m + 1))*(c + d*x)*((a + b*x^2)^(p + 1)/(2*a*e*(p + 1) 
)), x] + Simp[1/(2*a*(p + 1))   Int[(e*x)^m*(c*(m + 2*p + 3) + d*(m + 2*p + 
 4)*x)*(a + b*x^2)^(p + 1), x], x] /; FreeQ[{a, b, c, d, e, m}, x] && LtQ[p 
, -1] && LtQ[m, 0]
 

rule 555
Int[((f_) + (g_.)*(x_))/(Sqrt[x_]*Sqrt[(a_) + (c_.)*(x_)^2]), x_Symbol] :> 
Simp[2   Subst[Int[(f + g*x^2)/Sqrt[a + c*x^4], x], x, Sqrt[x]], x] /; Free 
Q[{a, c, f, g}, x]
 

rule 556
Int[((c_) + (d_.)*(x_))/(Sqrt[(e_)*(x_)]*Sqrt[(a_) + (b_.)*(x_)^2]), x_Symb 
ol] :> Simp[Sqrt[x]/Sqrt[e*x]   Int[(c + d*x)/(Sqrt[x]*Sqrt[a + b*x^2]), x] 
, x] /; FreeQ[{a, b, c, d, e}, x]
 

rule 761
Int[1/Sqrt[(a_) + (b_.)*(x_)^4], x_Symbol] :> With[{q = Rt[b/a, 4]}, Simp[( 
1 + q^2*x^2)*(Sqrt[(a + b*x^4)/(a*(1 + q^2*x^2)^2)]/(2*q*Sqrt[a + b*x^4]))* 
EllipticF[2*ArcTan[q*x], 1/2], x]] /; FreeQ[{a, b}, x] && PosQ[b/a]
 

rule 1510
Int[((d_) + (e_.)*(x_)^2)/Sqrt[(a_) + (c_.)*(x_)^4], x_Symbol] :> With[{q = 
 Rt[c/a, 4]}, Simp[(-d)*x*(Sqrt[a + c*x^4]/(a*(1 + q^2*x^2))), x] + Simp[d* 
(1 + q^2*x^2)*(Sqrt[(a + c*x^4)/(a*(1 + q^2*x^2)^2)]/(q*Sqrt[a + c*x^4]))*E 
llipticE[2*ArcTan[q*x], 1/2], x] /; EqQ[e + d*q^2, 0]] /; FreeQ[{a, c, d, e 
}, x] && PosQ[c/a]
 

rule 1512
Int[((d_) + (e_.)*(x_)^2)/Sqrt[(a_) + (c_.)*(x_)^4], x_Symbol] :> With[{q = 
 Rt[c/a, 2]}, Simp[(e + d*q)/q   Int[1/Sqrt[a + c*x^4], x], x] - Simp[e/q 
 Int[(1 - q*x^2)/Sqrt[a + c*x^4], x], x] /; NeQ[e + d*q, 0]] /; FreeQ[{a, c 
, d, e}, x] && PosQ[c/a]
 
3.5.81.4 Maple [A] (verified)

Time = 1.42 (sec) , antiderivative size = 404, normalized size of antiderivative = 1.21

method result size
elliptic \(\frac {\sqrt {\left (c \,x^{2}+a \right ) e x}\, \left (\frac {\left (\frac {B x}{3 a e \,c^{2}}+\frac {A}{3 a e \,c^{2}}\right ) \sqrt {c e \,x^{3}+a e x}}{\left (x^{2}+\frac {a}{c}\right )^{2}}-\frac {2 c e x \left (-\frac {B x}{4 a^{2} e c}-\frac {5 A}{12 a^{2} e c}\right )}{\sqrt {\left (x^{2}+\frac {a}{c}\right ) x e c}}+\frac {5 A \sqrt {-a c}\, \sqrt {\frac {\left (x +\frac {\sqrt {-a c}}{c}\right ) c}{\sqrt {-a c}}}\, \sqrt {-\frac {2 \left (x -\frac {\sqrt {-a c}}{c}\right ) c}{\sqrt {-a c}}}\, \sqrt {-\frac {x c}{\sqrt {-a c}}}\, F\left (\sqrt {\frac {\left (x +\frac {\sqrt {-a c}}{c}\right ) c}{\sqrt {-a c}}}, \frac {\sqrt {2}}{2}\right )}{12 a^{2} c \sqrt {c e \,x^{3}+a e x}}-\frac {B \sqrt {-a c}\, \sqrt {\frac {\left (x +\frac {\sqrt {-a c}}{c}\right ) c}{\sqrt {-a c}}}\, \sqrt {-\frac {2 \left (x -\frac {\sqrt {-a c}}{c}\right ) c}{\sqrt {-a c}}}\, \sqrt {-\frac {x c}{\sqrt {-a c}}}\, \left (-\frac {2 \sqrt {-a c}\, E\left (\sqrt {\frac {\left (x +\frac {\sqrt {-a c}}{c}\right ) c}{\sqrt {-a c}}}, \frac {\sqrt {2}}{2}\right )}{c}+\frac {\sqrt {-a c}\, F\left (\sqrt {\frac {\left (x +\frac {\sqrt {-a c}}{c}\right ) c}{\sqrt {-a c}}}, \frac {\sqrt {2}}{2}\right )}{c}\right )}{4 a^{2} c \sqrt {c e \,x^{3}+a e x}}\right )}{\sqrt {e x}\, \sqrt {c \,x^{2}+a}}\) \(404\)
default \(\frac {5 A \sqrt {-a c}\, \sqrt {\frac {c x +\sqrt {-a c}}{\sqrt {-a c}}}\, \sqrt {2}\, \sqrt {\frac {-c x +\sqrt {-a c}}{\sqrt {-a c}}}\, \sqrt {-\frac {x c}{\sqrt {-a c}}}\, F\left (\sqrt {\frac {c x +\sqrt {-a c}}{\sqrt {-a c}}}, \frac {\sqrt {2}}{2}\right ) c \,x^{2}+3 B \sqrt {\frac {c x +\sqrt {-a c}}{\sqrt {-a c}}}\, \sqrt {2}\, \sqrt {\frac {-c x +\sqrt {-a c}}{\sqrt {-a c}}}\, \sqrt {-\frac {x c}{\sqrt {-a c}}}\, F\left (\sqrt {\frac {c x +\sqrt {-a c}}{\sqrt {-a c}}}, \frac {\sqrt {2}}{2}\right ) a c \,x^{2}-6 B \sqrt {\frac {c x +\sqrt {-a c}}{\sqrt {-a c}}}\, \sqrt {2}\, \sqrt {\frac {-c x +\sqrt {-a c}}{\sqrt {-a c}}}\, \sqrt {-\frac {x c}{\sqrt {-a c}}}\, E\left (\sqrt {\frac {c x +\sqrt {-a c}}{\sqrt {-a c}}}, \frac {\sqrt {2}}{2}\right ) a c \,x^{2}+5 A \sqrt {\frac {c x +\sqrt {-a c}}{\sqrt {-a c}}}\, \sqrt {2}\, \sqrt {\frac {-c x +\sqrt {-a c}}{\sqrt {-a c}}}\, \sqrt {-\frac {x c}{\sqrt {-a c}}}\, F\left (\sqrt {\frac {c x +\sqrt {-a c}}{\sqrt {-a c}}}, \frac {\sqrt {2}}{2}\right ) \sqrt {-a c}\, a +3 B \sqrt {\frac {c x +\sqrt {-a c}}{\sqrt {-a c}}}\, \sqrt {2}\, \sqrt {\frac {-c x +\sqrt {-a c}}{\sqrt {-a c}}}\, \sqrt {-\frac {x c}{\sqrt {-a c}}}\, F\left (\sqrt {\frac {c x +\sqrt {-a c}}{\sqrt {-a c}}}, \frac {\sqrt {2}}{2}\right ) a^{2}-6 B \sqrt {\frac {c x +\sqrt {-a c}}{\sqrt {-a c}}}\, \sqrt {2}\, \sqrt {\frac {-c x +\sqrt {-a c}}{\sqrt {-a c}}}\, \sqrt {-\frac {x c}{\sqrt {-a c}}}\, E\left (\sqrt {\frac {c x +\sqrt {-a c}}{\sqrt {-a c}}}, \frac {\sqrt {2}}{2}\right ) a^{2}+6 B \,c^{2} x^{4}+10 A \,c^{2} x^{3}+10 a B c \,x^{2}+14 a A c x}{12 c \sqrt {e x}\, a^{2} \left (c \,x^{2}+a \right )^{\frac {3}{2}}}\) \(581\)

input
int((B*x+A)/(e*x)^(1/2)/(c*x^2+a)^(5/2),x,method=_RETURNVERBOSE)
 
output
((c*x^2+a)*e*x)^(1/2)/(e*x)^(1/2)/(c*x^2+a)^(1/2)*((1/3/a/e/c^2*B*x+1/3/a/ 
e/c^2*A)*(c*e*x^3+a*e*x)^(1/2)/(x^2+a/c)^2-2*c*e*x*(-1/4/a^2/e*B/c*x-5/12/ 
a^2/e*A/c)/((x^2+a/c)*x*e*c)^(1/2)+5/12*A/a^2*(-a*c)^(1/2)/c*((x+(-a*c)^(1 
/2)/c)/(-a*c)^(1/2)*c)^(1/2)*(-2*(x-(-a*c)^(1/2)/c)/(-a*c)^(1/2)*c)^(1/2)* 
(-x/(-a*c)^(1/2)*c)^(1/2)/(c*e*x^3+a*e*x)^(1/2)*EllipticF(((x+(-a*c)^(1/2) 
/c)/(-a*c)^(1/2)*c)^(1/2),1/2*2^(1/2))-1/4/a^2*B*(-a*c)^(1/2)/c*((x+(-a*c) 
^(1/2)/c)/(-a*c)^(1/2)*c)^(1/2)*(-2*(x-(-a*c)^(1/2)/c)/(-a*c)^(1/2)*c)^(1/ 
2)*(-x/(-a*c)^(1/2)*c)^(1/2)/(c*e*x^3+a*e*x)^(1/2)*(-2*(-a*c)^(1/2)/c*Elli 
pticE(((x+(-a*c)^(1/2)/c)/(-a*c)^(1/2)*c)^(1/2),1/2*2^(1/2))+(-a*c)^(1/2)/ 
c*EllipticF(((x+(-a*c)^(1/2)/c)/(-a*c)^(1/2)*c)^(1/2),1/2*2^(1/2))))
 
3.5.81.5 Fricas [C] (verification not implemented)

Result contains higher order function than in optimal. Order 9 vs. order 4.

Time = 0.10 (sec) , antiderivative size = 164, normalized size of antiderivative = 0.49 \[ \int \frac {A+B x}{\sqrt {e x} \left (a+c x^2\right )^{5/2}} \, dx=\frac {5 \, {\left (A c^{2} x^{4} + 2 \, A a c x^{2} + A a^{2}\right )} \sqrt {c e} {\rm weierstrassPInverse}\left (-\frac {4 \, a}{c}, 0, x\right ) + 3 \, {\left (B c^{2} x^{4} + 2 \, B a c x^{2} + B a^{2}\right )} \sqrt {c e} {\rm weierstrassZeta}\left (-\frac {4 \, a}{c}, 0, {\rm weierstrassPInverse}\left (-\frac {4 \, a}{c}, 0, x\right )\right ) + {\left (3 \, B c^{2} x^{3} + 5 \, A c^{2} x^{2} + 5 \, B a c x + 7 \, A a c\right )} \sqrt {c x^{2} + a} \sqrt {e x}}{6 \, {\left (a^{2} c^{3} e x^{4} + 2 \, a^{3} c^{2} e x^{2} + a^{4} c e\right )}} \]

input
integrate((B*x+A)/(e*x)^(1/2)/(c*x^2+a)^(5/2),x, algorithm="fricas")
 
output
1/6*(5*(A*c^2*x^4 + 2*A*a*c*x^2 + A*a^2)*sqrt(c*e)*weierstrassPInverse(-4* 
a/c, 0, x) + 3*(B*c^2*x^4 + 2*B*a*c*x^2 + B*a^2)*sqrt(c*e)*weierstrassZeta 
(-4*a/c, 0, weierstrassPInverse(-4*a/c, 0, x)) + (3*B*c^2*x^3 + 5*A*c^2*x^ 
2 + 5*B*a*c*x + 7*A*a*c)*sqrt(c*x^2 + a)*sqrt(e*x))/(a^2*c^3*e*x^4 + 2*a^3 
*c^2*e*x^2 + a^4*c*e)
 
3.5.81.6 Sympy [C] (verification not implemented)

Result contains complex when optimal does not.

Time = 57.98 (sec) , antiderivative size = 94, normalized size of antiderivative = 0.28 \[ \int \frac {A+B x}{\sqrt {e x} \left (a+c x^2\right )^{5/2}} \, dx=\frac {A \sqrt {x} \Gamma \left (\frac {1}{4}\right ) {{}_{2}F_{1}\left (\begin {matrix} \frac {1}{4}, \frac {5}{2} \\ \frac {5}{4} \end {matrix}\middle | {\frac {c x^{2} e^{i \pi }}{a}} \right )}}{2 a^{\frac {5}{2}} \sqrt {e} \Gamma \left (\frac {5}{4}\right )} + \frac {B x^{\frac {3}{2}} \Gamma \left (\frac {3}{4}\right ) {{}_{2}F_{1}\left (\begin {matrix} \frac {3}{4}, \frac {5}{2} \\ \frac {7}{4} \end {matrix}\middle | {\frac {c x^{2} e^{i \pi }}{a}} \right )}}{2 a^{\frac {5}{2}} \sqrt {e} \Gamma \left (\frac {7}{4}\right )} \]

input
integrate((B*x+A)/(e*x)**(1/2)/(c*x**2+a)**(5/2),x)
 
output
A*sqrt(x)*gamma(1/4)*hyper((1/4, 5/2), (5/4,), c*x**2*exp_polar(I*pi)/a)/( 
2*a**(5/2)*sqrt(e)*gamma(5/4)) + B*x**(3/2)*gamma(3/4)*hyper((3/4, 5/2), ( 
7/4,), c*x**2*exp_polar(I*pi)/a)/(2*a**(5/2)*sqrt(e)*gamma(7/4))
 
3.5.81.7 Maxima [F]

\[ \int \frac {A+B x}{\sqrt {e x} \left (a+c x^2\right )^{5/2}} \, dx=\int { \frac {B x + A}{{\left (c x^{2} + a\right )}^{\frac {5}{2}} \sqrt {e x}} \,d x } \]

input
integrate((B*x+A)/(e*x)^(1/2)/(c*x^2+a)^(5/2),x, algorithm="maxima")
 
output
integrate((B*x + A)/((c*x^2 + a)^(5/2)*sqrt(e*x)), x)
 
3.5.81.8 Giac [F]

\[ \int \frac {A+B x}{\sqrt {e x} \left (a+c x^2\right )^{5/2}} \, dx=\int { \frac {B x + A}{{\left (c x^{2} + a\right )}^{\frac {5}{2}} \sqrt {e x}} \,d x } \]

input
integrate((B*x+A)/(e*x)^(1/2)/(c*x^2+a)^(5/2),x, algorithm="giac")
 
output
integrate((B*x + A)/((c*x^2 + a)^(5/2)*sqrt(e*x)), x)
 
3.5.81.9 Mupad [F(-1)]

Timed out. \[ \int \frac {A+B x}{\sqrt {e x} \left (a+c x^2\right )^{5/2}} \, dx=\int \frac {A+B\,x}{\sqrt {e\,x}\,{\left (c\,x^2+a\right )}^{5/2}} \,d x \]

input
int((A + B*x)/((e*x)^(1/2)*(a + c*x^2)^(5/2)),x)
 
output
int((A + B*x)/((e*x)^(1/2)*(a + c*x^2)^(5/2)), x)